/*  C program to accept a matrix of order MxN and find its transpose */

#include <stdio.h>
void main ()
{
static int ma[10][10];
int i,j,m,n;

printf (“Enter the order of the matrix \n”);
scanf (“%d %d”,&m,&n);

printf (“Enter the coefficients of the matrix\n”);
for (i=0;i<m;++i)
{
for (j=0;j<n;++j)
{
scanf (“%d”,&ma[i][j]);
}
}
printf (“The given matrix is \n”);
for (i=0;i<m;++i)
{
for (j=0;j<n;++j)
{
printf (” %d”,ma[i][j]);
}
printf (“\n”);
}

printf (“Transpose of matrix is \n”);
for (j=0;j<n;++j)
{
for (i=0;i<m;++i)
{
printf (” %d”,ma[i][j]);
}
printf (“\n”);
}
}      /* End of main() */

/*——————————————
Output
Enter the order of the matrix
2 2
Enter the coefficients of the matrix
3 -1
6 0
The given matrix is
3 -1
6 0
Transpose of matrix is
3 6
-1 0

——————————————-*/

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