/*  C program to accept a string and find the sum of  all digits present in the string  */

#include <stdio.h>
void main()
{
char string[80];
int count,nc=0,sum=0;

printf(“Enter the string containing both digits and alphabet\n”);
scanf(“%s”,string);

for(count=0;string[count]!=’\0′; count++)
{
if((string[count]>=’0′) && (string[count]<=’9′))
{
nc += 1;
sum += (string[count] – ’0′);
}      /* End of if */
}         /* End of For */

printf(“NO. of Digits in the string=%d\n”,nc);
printf(“Sum of all digits=%d\n”,sum);

}         /* End of main() */

/*—————————————————–
Output
Enter the string containing both digits and alphabet
goodmorning25
NO. of Digits in the string=2
Sum of all digits=7

——————————————————–*/

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