C program to find and output all the roots of a quadratic equation, for non-zero coefficients.

by Nideesh C on April 12, 2011 · 0 comments

in C Programming




/* write a C program to find and output all the roots of a quadratic equation, for non-zero coefficients. In case of errors your program should report suitable error message */

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <math.h>

void main()
{
float A, B, C, root1, root2;
float realp, imagp, disc;

clrscr();

printf(“Enter the values of A, B and C\n”);
scanf(“%f %f %f”, &A,&B,&C);

/* If A = 0, it is not a quadratic equation */

if( A==0 || B==0 || C==0)
{
printf(“Error: Roots cannot be determined\n”);
exit(1);
}
else
{
disc = B*B – 4.0*A*C;
if(disc < 0)
{
printf(“Imaginary Roots\n”);
realp = -B/(2.0*A) ;
imagp = sqrt(abs(disc))/(2.0*A);
printf(“Root1 = %f  +i %f\n”,realp, imagp);
printf(“Root2 = %f  -i %f\n”,realp, imagp);
}
else if(disc == 0)
{
printf(“Roots are real and equal\n”);
root1 = -B/(2.0*A);
root2 = root1;
printf(“Root1 = %f  \n”,root1);
printf(“Root2 = %f  \n”,root2);
}
else if(disc > 0 )
{
printf(“Roots are real and distinct\n”);
root1 =(-B+sqrt(disc))/(2.0*A);
root2 =(-B-sqrt(disc))/(2.0*A);
printf(“Root1 = %f  \n”,root1);
printf(“Root2 = %f  \n”,root2);
}
}

}   /* End of main() */

/*—————————
Output
RUN 1
Enter the values of A, B and C
3 2 1
Imaginary Roots
Root1 = -0.333333  +i 0.471405
Root2 = -0.333333  -i 0.471405

RUN 2
Enter the values of A, B and C
1 2 1
Roots are real and equal
Root1 = -1.000000
Root2 = -1.000000

RUN 3
Enter the values of A, B and C
3 5 2
Roots are real and distinct
Root1 = -0.666667
Root2 = -1.000000
———————————*/

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