/*  C program to find the sum of two one-dimensional arrays using  Dynamic Memory Allocation */

#include <stdio.h>
#include <alloc.h>
#include <stdlib.h>

void main()
{
int i,n;
int *a,*b,*c;

printf(“How many Elements in each array…\n”);
scanf(“%d”, &n);

a = (int *) malloc(n*sizeof(int));
b = (int *) malloc(n*sizeof(int));
c =( int *) malloc(n*sizeof(int));

printf(“Enter Elements of First List\n”);
for(i=0;i<n;i++)
{
scanf(“%d”,a+i);
}

printf(“Enter Elements of Second List\n”);
for(i=0;i<n;i++)
{
scanf(“%d”,b+i);
}

for(i=0;i<n;i++)
{
*(c+i) = *(a+i) + *(b+i);
}

printf(“Resultant List is\n”);
for(i=0;i<n;i++)
{
printf(“%d\n”,*(c+i));
}

}     /* End of main() */

/*—————————————
Output
How many Elements in each array…
4
Enter Elements of First List
1
2
3
4
Enter Elements of Second List
6
7
8
9
Resultant List is
7
9
11
13

—————————————-*/

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