C program to illustrate the operations of singly linked list

by Nideesh C on April 13, 2011 · 0 comments

in C Programming




/* C program to illustrate the operations of singly linked list */

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>
#define MAX 30

struct EMP
{
int  empno;
char empName[MAX];
char designation[MAX];
struct EMP *next;
};

/*********************************************************************/
/* Function to insert a node at the front of the linked list.        */
/* front: front pointer, id: employee ID, name: employee name        */
/* desg: Employee designation                          */
/* Returns the new front pointer.                                    */
/*********************************************************************/

struct EMP* insert(struct EMP *front, int id, char name[], char desg[])
{
struct EMP *newnode;

newnode = (struct EMP*) malloc(sizeof(struct EMP));

if (newnode == NULL)
{
printf(“\nAllocation failed\n”);
exit(2);
}
newnode->empno = id;
strcpy(newnode->empName, name);
strcpy(newnode->designation, desg);
newnode->next = front;
front = newnode;
return(front);
}                                /*End of insert() */

/* Function to display a node in a linked list */
void printNode(struct EMP *p)
{
printf(“\nEmployee Details…\n”);
printf(“\nEmp No       : %d”, p->empno);
printf(“\nName           : %s”, p->empName);
printf(“\nDesignation    : %s\n”, p->designation);
printf(“————————————-\n”);
}                                  /*End of printNode() */

/* ********************************************************/
/* Function to deleteNode a node based on employee number     */
/* front: front pointer, id: Key value                    */
/* Returns: the modified list.                            */
/* ********************************************************/

struct EMP* deleteNode(struct EMP *front, int id)
{
struct EMP *ptr;
struct EMP *bptr;    /* bptr is pointing to the node behind ptr */

if (front->empno == id)
{
ptr = front;
printf(“\nNode deleted:”);
printNode(front);
front = front->next;
free(ptr);
return(front);
}

for(ptr=front->next, bptr=front; ptr!=NULL; ptr=ptr->next, bptr=bptr->next)
{
if (ptr->empno == id)
{
printf(“\nNode deleted:”);
printNode(ptr);
bptr->next = ptr->next;
free(ptr);
return(front);
}
}
printf(“\nEmployee Number %d not found “, id);
return(front);
}                                 /*End of deleteNode() */

/*****************************************************************/
/* Function to search the nodes in a linear fashion based emp ID */
/* front: front pointer, key: key ID.                             */
/*****************************************************************/
void search(struct EMP *front, int key)
{
struct EMP *ptr;

for (ptr = front; ptr != NULL; ptr = ptr -> next)
{
if (ptr->empno == key)
{
printf(“\nKey found:”);
printNode(ptr);
return;
}
}
printf(“\nEmployee Number %d not found “, key);
}                              /*End of search() */

/* Function to display the linked list */
void display(struct EMP *front)
{
struct EMP *ptr;

for (ptr = front; ptr != NULL; ptr = ptr->next)
{
printNode(ptr);
}
}                            /*End of display() */

/* Function to display the menu of operations on a linked list */
void menu()
{
printf(“———————————————\n”);
printf(“Press 1 to INSERT a node into the list       \n”);
printf(“Press 2 to DELETE a node from the list       \n”);
printf(“Press 3 to DISPLAY the list                  \n”);
printf(“Press 4 to SEARCH the list                   \n”);
printf(“Press 5 to EXIT                              \n”);
printf(“———————————————\n”);
}                         /*End of menu() */

/* Function to select the option */
char option()
{
char choice;

printf(“\n\n>> Enter your choice: “);
switch(choice=getche())
{
case ’1′:
case ’2′:
case ’3′:
case ’4′:
case ’5′:   return(choice);
default :    printf(“\nInvalid choice.”);
}
return choice;
}                           /*End of option() */

/* The main() program begins */
void main()
{
struct EMP *linkList;
char name[21], desig[51];
char choice;
int eno;

linkList = NULL;

printf(“\nWelcome to demonstration of singly linked list\n”);

menu();             /*Function call */

do {
choice = option();          /*to choose operation to be performed */

switch(choice)
{
case ’1′: printf(“\nEnter the Employee Number      : “);
scanf(“%d”, &eno);

printf(“Enter the Employee name        : “);
fflush(stdin);
gets(name);

printf(“Enter the Employee Designation : “);
gets(desig);

linkList = insert(linkList, eno, name, desig);
break;

case ’2′: printf(“\n\nEnter the employee number to be deleted: “);
scanf(“%d”, &eno);

linkList = deleteNode(linkList, eno);
break;

case ’3′: if (linkList == NULL)
{
printf(“\nList empty.”);
break;
}
display(linkList);
break;

case ’4′: printf(“\n\nEnter the employee number to be searched: “);
scanf(“%d”, &eno);

search(linkList, eno);
break;

case ’5′: break;
}
} while (choice != ’5′);
}                                     /*End of main()*/

/*——————————————————————————
Output

Welcome to demonstration of singly linked list
———————————————
Press 1 to INSERT a node into the list
Press 2 to DELETE a node from the list
Press 3 to DISPLAY the list
Press 4 to SEARCH the list
Press 5 to EXIT
———————————————

>> Enter your choice: 1
Enter the Employee Number      : 1234
Enter the Employee name        : Keerthi
Enter the Employee Designation : Engineer

>> Enter your choice: 1
Enter the Employee Number      : 2345
Enter the Employee name        : Srinivasan
Enter the Employee Designation : Specilist

>> Enter your choice: 1
Enter the Employee Number      : 4567
Enter the Employee name        : Annapoorna
Enter the Employee Designation : Project Manager

>> Enter your choice: 3
Employee Details…

Emp No    : 4567
Name        : Annapoorna
Designation : Project Manager
————————————-

Employee Details…

Emp No    : 2345
Name        : Srinivasan
Designation : Specialist
————————————-

Employee Details…

Emp No    : 1234
Name        : Keerthi
Designation : Engineer
————————————-

>> Enter your choice: 2

Enter the employee number to be deleted: 2345

Node deleted:
Employee Details…

Emp No    : 2345
Name        : Srinivasan
Designation : Specialist
————————————-

>> Enter your choice: 3
Employee Details…

Emp No    : 4567
Name        : Annapoorna
Designation : Project Manager
————————————-

Employee Details…

Emp No    : 1234
Name        : Keerthi
Designation : Engineer
————————————-

>> Enter your choice: 4

Enter the employee number to be searched: 2345

Employee Number 2345 not found

>> Enter your choice: 5

——————————————————————————*/

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